A

In the given diagram, we observe a concave mirror and the object placed at a distance of 30 cm from the mirror. Applying the mirror formula, \( \frac{1}{f} = \frac{1}{u} + \frac{1}{v} \), where \( f \) is the focal length, \( u \) is the object distance, and \( v \) is the image distance.
For a concave mirror, the focal length \( f \) is negative and is given as \( f = -15 \) cm (since the focal length is half of the radius of curvature, which is 30 cm). Using the mirror formula:

• Substituting the values:
  \( \frac{1}{-15} = \frac{1}{-30} + \frac{1}{v} \)
• Rearranging gives us: \( \frac{1}{v} = \frac{1}{-15} + \frac{1}{30} = -\frac{2}{30} + \frac{1}{30} = -\frac{1}{30} \)
• Therefore, \( v = -30 \) cm, indicating that the image is virtual and on the same side as the object.
  

The negative value confirms the image is behind the mirror. Therefore, the image's velocity is determined by the speed of light in the respective medium, typically approximated as the speed of light in a vacuum: 300,000 km/s or 3 x 10^8 m/s. Hence, the final calculated velocity is a function of positioning rather than object velocity.